-15x^2+1950x-60000=0

Solution for -15x^2+1950x-60000=0 equation:

-15x^2+1950x-60000=0

a = -15; b = 1950; c = -60000;
Δ = b2-4ac
Δ = 19502-4·(-15)·(-60000)
Δ = 202500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{202500}=450$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1950)-450}{2*-15}=\frac{-2400}{-30}
=+80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1950)+450}{2*-15}=\frac{-1500}{-30}
=+50
$